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How does this code work? (sh.itjust.works)

submitted 1 month ago by zarkanian@sh.itjust.works to c/bash@lemmy.ml

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I'm studying bash, and I came across this Stackoverflow thread which contains this bit of code:

var="abcde"
echo ${var%d*}

The output is abc, but I can't figure out why. I understand that %d is used to indicate an integer number and * represents anything, but I can't figure out why those together would truncate var to only 3 characters.

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[–] bbpngn 1 points 1 day ago

You may be confusing that %d with printf syntax. I'm not entirely sure, but I think what the percent sign means is delete everything from the end of string until the first occurence of letter "d"