this post was submitted on 02 Apr 2025
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I replaced this battery last fall, but it has drained over the winter. The auto-mower dock wont charge it. Is there any feasible way to charge it safely? Or is it dead at that voltage? It’s a Bosch Indego 400. Thanks in advance.

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[–] guy_threepwood@lemmy.world 14 points 3 days ago (3 children)

I am assuming that 18v is 5 cells in series, with a nominal voltage of 3.7 x 5 = 18.5 volts. At 15.22 each cell is around 3 volts. 3 volts is usually considered the absolute minimum you can discharge cells to. (3.3v is considered flat) If it won’t charge, it’s probably dead.

It might be possible to rig up a charger to very very slowly charge the battery up to about 3.3 volts, at which point the proper charger might agree to fully charge the battery, but with the cells already below 3.3v there’s a good chance it won’t work even if you did that. And it’s not without risks.

[–] wiegell@feddit.dk 5 points 2 days ago (1 children)

And also: is a depleted battery more likely to short circuit and overheat?

Even if that worked, these cells will never be able to hold a significant charge.

[–] wiegell@feddit.dk 2 points 2 days ago (1 children)

Thank you for the elaborate response. Does this seem reasonable: Charging voltage 5 * 3,3v = 16,5v, charging current limit 100mA? And then put the whole thing in the garden? Would you take breaks?

[–] guy_threepwood@lemmy.world 5 points 2 days ago (1 children)

I’d go even lower, maybe 50mA. The main issue you’re fighting is internal resistance, which will cause things to heat up. Your other issue is that I’ve averaged things, however it’s quite likely that one or more cells has a significantly lower voltage than others (and therefore a higher resistance) so can cause more risk.

If you’re able to get the pack apart and measure the cells separately that will help a lot

[–] Onomatopoeia@lemmy.cafe 5 points 2 days ago

If you can get the pack apart, I'd just rebuild it. Replacement cells are as little as $2 each.