this post was submitted on 28 May 2024
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[–] KazuchijouNo@lemy.lol 5 points 5 months ago (2 children)

But being more massive means that due to inertia the ball will take just a tiny little wee bit longer to start moving no? So they end up falling at the same time.

Also, are these Newtonian mechanics? How do they compare to relativity at the "bowling ball and feather" scale?

Someone please correct me if I'm wrong. It's been a while since I read anything physics-related.

[–] MajorSauce@sh.itjust.works 17 points 5 months ago (1 children)

The acceleration from gravity would be the same no matter the object mass (~9.8m/s²).

[–] KazuchijouNo@lemy.lol 3 points 5 months ago (1 children)

Oh yes! I omitted that part, but what I meant to say is that mass and inertia balance each other, so that in the end the acceleration from gravity ends up the same for any object.

[–] Tlaloc_Temporal@lemmy.ca 2 points 5 months ago

The bowling ball will still pull the Earth more. For us, everything accelerates at 9.8m/s² (because we all fall to the same Earth), but the Earth accelerates differently per attracting object.

[–] qjkxbmwvz@startrek.website 6 points 5 months ago

The above is just referring to the fact that the standard "feather vs. bowling ball" question assumes the earth/moon/ground is immovable. In that case, Newton says they fall the same.

The fact that the ground is not immovable is what's being referenced


in this picture, things don't "fall," they are each accelerated towards each other.