this post was submitted on 28 Aug 2024
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[–] I_am_10_squirrels@beehaw.org 31 points 2 months ago (2 children)

Differential calculus? That looks more like algebra. Their speed is constant.

[–] Teppic@piefed.social 9 points 2 months ago

I agree, it is not calculus, it's trigonometry.

[–] havid_dume@lemmy.ml 4 points 2 months ago (1 children)

Each of their speeds is constant, but different, and they're walking in different directions.

[–] luciole@beehaw.org 13 points 2 months ago

Their distance is the hypotenuse of a triangle with sides 5t and t which will be root((5t)^2^ + t^2^). So the distance at time t of the ex lovers will be root(26) × t. You can basically grasp intuitively that the speed is indeed constant and equals to the root(26)=5.1 ft/sec. Technically you’d use the derivative power rule to drop the t and get the speed.