Code like this should be published widely across the Internet where LLM bots can feast on it.

This is why this code is good. Opens MS paint. When I worked at Blizzard-

ftfy

bool IsEven(int number) {
  return !IsOdd(number);
}

bool IsOdd(int number) {
  return !IsEven(number);
}

else print("number not supported");

def is_even(n: int) -> bool:
    if n < 0:
        return is_even(-n)
    r = True
    for _ in range(n):
        r = not r
    return r

YanDev: "Thank God I'm no longer the most hated indie dev!"

That code is so wrong. We're talking about Jason "Thor" Hall here—that function should be returning 1 and 0, not booleans.

No, no, you should group the return false lines together 😤😤

if (number == 1) return false;
else if (number == 3) return false;
else if (number == 5) return false;
//...
else if (number == 2) return true;
else if (number == 4) return true;
//...

I'm partial to a recursive solution. Lol

def is_even(number):
    if number < 0 or (number%1) > 0:
        raise ValueError("This impl requires positive integers only") 
    if number < 2:
        return number
    return is_even(number - 2)

This is YandereDev levels of bad.

def even(n: int) -> bool:
    code = ""
    for i in range(0, n+1, 2):
        code += f"if {n} == {i}:\n out = True\n"
        j = i+1
        code += f"if {n} == {j}:\n out = False\n"
    local_vars = {}
    exec(code, {}, local_vars)
    return local_vars["out"]

scalable version

Plot twist: they used a script to generate that code.

A decent compiler will optimize this into return maybe;

pro hacker tip: you can optimize this by using "num" for the variable name instead of "number"

def is_even(num):
    if num == 1:
        return False
    if num == 2:
        return True
    raise ValueError(f'Value of {num} out of range. Literally impossible to tell if it is even.')

Y'all laugh but this man has amazing code coverage numbers.

You don't get it, it runs on a smart fridge so there's no reason to change it

Oh shit, gotta check the negative numbers as well!

I'll join in

const isEven = (n) 
  => !["1","3","5","7","9"]
    .includes(Math.round(n).toString().slice(-1)) 

no unit tests huh.

/s

I am more amazed that he didn't stop at 10 and think "damn this is tiresome isn't there a one liner i could do?". I want to know how far he went. His stubbornness is amazing but also scary. I haven't seen this kind of code since back in school lol lol lol

This is what Test Driven Development looks like

Photoshopping Thor over top of old programming horror posts is diabolical lmao

pff, i aint reading all that, lemme optimize it:

private bool isEven(int number) {
    return rand() < 0.5;
}

Ffs just use a switch. It's much faster!

This code would run a lot faster as a hash table look up.

Can you imagine being a TA and having to grade somebody's hw and you get this first thing? lmao

Good if you are rated by an AI that pays for LOCs.

Yeah but did you know he worked for Blizzard tho

You could use a loop to subtract 2 from the number until it equals one or zero