this post was submitted on 26 Jun 2024
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[–] FuglyDuck@lemmy.world 5 points 5 months ago (1 children)

A stationary aeroplane on a treadmill will obviously move with the treadmill. I assume an aeroplane moving at like 1 km/h still gets pulled backward by the treadmill.

so, every wheel or ball or any other kind of rolling-thing has rolling resistance, which is how we sum up the total drag on the system. A steel ball bearing on a steel plate will have a significantly lower rolling resistance than, say, a steel cube on that same plate. Tires have some- but not a lot- of rolling resistance.

You can see that in a car, just put it into neutral and watch as you slow down, even on flat ground. Plane wheels also have rolling resistance. it's just the way our world works. But it's generally ignored because it's hard to model perfectly and in any case pretty negligible relative to the amount of acceleration being put out by modern aircraft engines.

A treadmill will only push an aircraft or whatever else along, with an acceleration that is equal to, or lower, than the rolling resistance. If you try to accelerate the plane faster, it'll 'slip', and the plane will remain largely stationary- like the dishes in the tablecloth trick (if you want to try that at home... make sure the tablecloth doesn't have a hem, heh.)

But, keep in mind you're thinking about the plane relative to either the ground, or the treadmill's belt.

the plane's wings and it's engines are 'thinking' about the plane relative to the air it's moving through. It's the airspeed that generates the lift, and the engine isn't coupled to the wheels, they're just rolling along doing their thing. (aircraft engines work by taking a volume of air and accelerating it. newton's equal-and-opposite does the rest.)

[–] Zagorath@aussie.zone 2 points 5 months ago (1 children)

Oh wow thank you. This is genuinely excellent and immensely helpful. I think this bit:

A treadmill will only push an aircraft or whatever else along, with an acceleration that is equal to, or lower, than the rolling resistance. If you try to accelerate the plane faster, it’ll ‘slip’

As well as this video that I found where a pilot explains how under specific but unrealistic conditions you could construct a treadmill that does indeed prevent an aeroplane from taking off,

Really helped solidify my understanding of the problem. So you end up with a situation where the wheels are going to be slipping, just like the slippage created when your hand pushes a toy car on a treadmill.

Thanks!

[–] FuglyDuck@lemmy.world 2 points 5 months ago

So, another way to think about it is with Kites.

The air flows around it the same way it would any other kind of aircraft, though they have effectively zero ground speed.

They do differ in that, being tethered, they’re pulled through the air, with the wind providing the energy to stay up.

But they’re still moving through the air, and the airfoils are inducing drag to convert some of that energy into lift.

In both cases, the important speed is relative to the air, not the ground and not the treadmill. The wheels might impart some drag while they’re on the ground, but they’re never going to impart enough to overpower the engines- 747s typically take off at about 75% of their rated take off power, which means a longer take off roll, but less wear and tear.