You could use a loop to subtract 2 from the number until it equals one or zero

bool isEven(int value) {
  return (int)(((double)value / 2.0) % 1.0) * 100) != 50;
} 

No need to reinvent the wheel. Use the isEven API!

assert IsEven(-2);

IMO he's ragebaiting

This joke was not written by the dude pictured. The author wrote a book of funny code jokes.

What you do is use a for loop to generate a million lines for you, then paste it in. Writing it manually is moronic. You can easily make it support numbers above 1,000,000 too this way, talking about scalable

I want to assess coders by lines written! The more the better!

apart from everything else, have they never heard of a switch statement

Oh. I thought that was Elixir until I zoomed in.

that's some good code right there

To be fair, the question is "Write a function that simultaneously determines if the number is even and works as a timer"

I hope that the language's ints are at most 32 bits. For 8 bits it could even be written by hand & the source code for a 32 bit version would only take up avg_line_len * 4GiB space for the source code of the function. But it might take a bit of time to compile a version that supports the full range of 64 or 128 bit ints.

When did Thor become the dev for Yandere Simulator?