Isn't the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn't it be more correct to make it equal to ++i

[–] Knusper@feddit.de 0 points 1 year ago (1 children)

In the languages I know, i-=-1 or x=3 are not expressions, but rather statements, so they do not evaluate to a value.

So, this would be a compiler error:

a = (x=3)

[–] mfz@kbin.social 1 points 1 year ago

Well, not all languages allow for fun programming :)

[–] maiskanzler@feddit.de 0 points 1 year ago (1 children)

And that's why post- and pre-increment is non-existant in Python and Rust. It's an easy source for bugs for a noncritical abbreviation🤷

[–] Knusper@feddit.de -1 points 1 year ago

They're especially also a source of bugs, because they encourage manually incrementing indices and manually accessing array positions, which is almost never actually sensible.