this post was submitted on 19 Jun 2023

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i++ (programming.dev)

submitted 1 year ago by sisyphean@programming.dev to c/programmer_humor@programming.dev

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[–] mfz@kbin.social 0 points 1 year ago (4 children)

Isn't the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn't it be more correct to make it equal to ++i

[–] Knusper@feddit.de 0 points 1 year ago (1 children)

In the languages I know, i-=-1 or x=3 are not expressions, but rather statements, so they do not evaluate to a value.

So, this would be a compiler error:

a = (x=3)

[–] mfz@kbin.social 1 points 1 year ago

Well, not all languages allow for fun programming :)

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